WebConsider an arithmetic progression (AP) whose first term is a 1 (or) a and the common difference is d.. The sum of first n terms of an arithmetic progression when the n th term is NOT known is S n = (n/2) [2a + (n - 1) d]; The sum of first n terms of an arithmetic progression when the n th term(a n) is known is S n = n/2[a 1 + a n]; Example: Mr. Kevin … WebFeb 1, 2024 · The sum of the first n terms of an AP is given by Sn, = 3n^2 - 4n. Determine the AP and the 12th term. ← Prev Question Next Question → +3 votes 79.8k views asked Feb 1, 2024 in Mathematics by Kundan kumar (51.5k points) The sum of the first n terms of an AP is given by S n, = 3n 2 - 4n. Determine the AP and the 12 th term. arithmetic progression
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WebCorrect option is A) Given, S n=4n 2−n When n=1 , S 1=4(1) 2−1=4−1=3 Now, obviously, the sum of the first term will be the first term itself, as there are no other terms involved. When n=2 , S 2=4(2) 2−1=16=2=14 The sum of the first 2 terms is equal to a 1+a 2 Therefore, a 1+a 2=14 We have shown, above, that a 1=3 Substituting it in a 1+a 2=14, WebFeb 25, 2024 · how this formula is substituted in to the sum plzz explain step wise up to 8n-3 what u r thiking Advertisement Expert-Verified Answer 218 people found it helpful abhi178 …
WebMar 29, 2024 · Transcript. Ex 5.3, 3 In an AP (vi) Given a = 2, d = 8, Sn = 90, find n and an. Given a = 2, d = 8, Sn = 90 We can use formula Sn = 𝑛/2 (2𝑎+ (𝑛−1)𝑑) Putting a = 2, d = 8, Sn = 90 90 = 𝑛/2 (2 × 2+ (𝑛−1) × 8) 90 = 𝑛/2 (4+8𝑛−8) 90 × 2 =𝑛 (4+8𝑛−8) 180 = n (8n – 4) 180 = 8n2 – 4n –180 + 8n2 – 4n = 0 ... WebFind many great new & used options and get the best deals for @+ Telecarte 50U - Le Jardin du Cheminot - Ref: En0746 - 3843ex at the best online prices at eBay! ... Télécarte F134 OISEAU BLEU en SC4OB variété non référencée SN sans n° de lot. ... Télécarte F224 EGT variété 4n°GE + 1n°PE rectifiant 1n°GE 34840 cote LUXE 140€ ...
WebSep 20, 2024 · Sn =n ( 4n + 1 ) = 4n^2 + n we know that, Tn = Sn - S (n-1) =4n^2+n -4 (n-1)^2 - (n-1) =4 (n^2-n^2+2n-1)+ (n-n+1) =8n - 4 + 1 = 8n -3 hence , Tn = 8n -3 T1 =8 (1)-3 =5 T2= 8 (2)-3 =13 so, AP is 5, 13 , 21 and so on Find Math textbook solutions? Class 7 Class 6 Class 5 Class 4 Class 3 Class 2 Class 1 NCERT Class 9 Mathematics 619 solutions WebJan 20, 2014 · In an A.P.,if Sn = n (4n+1) ,find the A.P. Share with your friends 2 Follow 4 Varun.Rawat, Meritnation Expert added an answer, on 21/1/14 We have, S n = 4n 2 + n put n = 1, we get S 1 = 4 (1) 2 + 1 = 4 + 1 = 5 So, First term, a 1 = 5 Put n = 2 , we get S 2 = 4 (2) 2 + 2 = 18 so, a 2 = S 2 - S 1 = 18 - 5 = 13 Put n = 3, we get S 3 = 4 (3) 2 + 3 = 39
WebJan 28, 2024 · In an AP, if Sn = n (4n + 1), find the AP - YouTube #class10#arithmeticprogressionsIn an AP, if Sn = n (4n + 1), find the AP …
WebSolution: Given, the expression for the sum of the terms is Sₙ = n (4n + 1) We have to find the AP. Put n = 1, S₁ = 1 (4 (1) + 1) = 4 + 1 = 5. Put n =2, S₂ = 2 (4 (2) + 1) = 2 (8 + 1) = 2 (9) = … labyrinthian definitionWebIn the given AP, the first term is a = 7 and the common difference is d = 4. Let us assume that 301 is the n th term of AP. Then: T n = a + (n - 1)d 301 = 7 + (n - 1) 4 301 = 7 + 4n - 4 301 = 4n + 3 298 = 4n n = 74.5 But 'n' must be an integer. Hence 301 cannot be a term of the given AP. Answer: 301 cannot be a term of the given AP. pronounce ibukunoluwaWebIn an AP, if S n=n(4n+1), fill the AP is 5, 13, __, --- Medium Solution Verified by Toppr Correct option is A 21 S n=n(4n+1) ∴S 1=a=1(4+1)=5 and S 2=a 1+a 2=2(4×2+1)=18 ⇒a+a+d=18⇒2a+d=18 ⇒d=18−2a=18−10=8 Therefore the AP is a,a+d,a+2d,.... i.e. 5,13,21,... Was this answer helpful? 0 0 Similar questions In an AP if a=1, a n=20 and S n=399, then n … labyrinthian maze skyrimWebGiven that sn = 4n^2 + 2n. ----- (1) Substitute n = 1 in (1), we get sn = 4(1)^2 + 2(1) = 4 + 2 = 6. So, Sum of the first term of AP is 6 i.e a = 6. Now, Substitute n = 2 in (1), we get sn = 4(2)^2 + 2(2) = 4 * 4 + 2 * 2 = 16 + 4 = 20. So, Sum of the first 2 terms = 20. Now, First-term + second term = 20 6 + a2 = 20 a2 = 20 - 6 a2 = 4. Hence in AP, labyrinthian doorWebIn an A.P, if S n=n(4n+1), find the general form of an A.P. Medium Solution Verified by Toppr S 1=a=5 {a= first term, d= common difference } S 2=a+(a+d)=2a+d=2(9) ⇒10+d=18 ⇒d=8 … labyrinthian bossesWebIn an AP, if Sn = n (4n+1), then find the AP. Solution We know that, the nth term of an AP is; an= Sn−Sn−1 an= n(4n+1)−(n−1){4(n−1)+1} [∵ Sn= n(4n+1)] ⇒ an =4n2+n−(n−1)(4n−3) ⇒ … pronounce hyundaiWebDefinition 1: A mathematical sequence in which the difference between two consecutive terms is always a constant and it is abbreviated as AP. Definition 2: An arithmetic sequence or progression is defined as a … pronounce i ching